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11 The tangent to the curve 
y=8x-x^(2) at the point 
(2,12) cuts the 
x-axis at the point 
P.
a Find the coordinates of 
P.
b Find the area of the shaded region.

1111 The tangent to the curve y=8xx2 y=8 x-x^{2} at the point (2,12) (2,12) cuts the x x -axis at the point P P .\newlinea Find the coordinates of P P .\newlineb Find the area of the shaded region.

Full solution

Q. 1111 The tangent to the curve y=8xx2 y=8 x-x^{2} at the point (2,12) (2,12) cuts the x x -axis at the point P P .\newlinea Find the coordinates of P P .\newlineb Find the area of the shaded region.
  1. Calculate Derivative and Slope: Calculate the derivative of y=8xx2y=8x-x^2 to find the slope of the tangent at the point (2,12)(2,12).dydx=82x\frac{dy}{dx} = 8 - 2xAt x=2x=2, dydx=82(2)=4\frac{dy}{dx} = 8 - 2(2) = 4.The slope of the tangent line at (2,12)(2,12) is 44.
  2. Write Tangent Line Equation: Write the equation of the tangent line using point-slope form.\newlineyy1=m(xx1)y - y_1 = m(x - x_1)\newliney12=4(x2)y - 12 = 4(x - 2)
  3. Find X-Intercept: Find where this tangent line intersects the x-axis by setting y=0y=0.\newline012=4(x2)0 - 12 = 4(x - 2)\newline12=4x8-12 = 4x - 8\newline4x=44x = 4\newlinex=1x = 1

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