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106106 is a root of f(x)=x2+11,236f(x) = x^2 + 11,236. Find the other roots of f(x)f(x).\newlineWrite your answer as a list of simplified values separated by commas, if there is more than one value.

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Q. 106106 is a root of f(x)=x2+11,236f(x) = x^2 + 11,236. Find the other roots of f(x)f(x).\newlineWrite your answer as a list of simplified values separated by commas, if there is more than one value.
  1. Write as x106x - 106: Since 106106 is a root, we can write it as x106=0x - 106 = 0. Now we need to find the other root.
  2. Find sum of roots: The sum of the roots of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is ba-\frac{b}{a}. In our case, a=1a = 1 and b=0b = 0, so the sum of the roots is 00.
  3. Determine other root: If one root is 106106, the other root must be 106-106 to sum up to 00.
  4. Determine other root: If one root is 106106, the other root must be 106-106 to sum up to 00.So the other root is 106-106.

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