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101101 is a root of f(x)=x2+10,201f(x) = x^2 + 10,201. Find the other roots of f(x)f(x).\newlineWrite your answer as a list of simplified values separated by commas, if there is more than one value.

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Q. 101101 is a root of f(x)=x2+10,201f(x) = x^2 + 10,201. Find the other roots of f(x)f(x).\newlineWrite your answer as a list of simplified values separated by commas, if there is more than one value.
  1. Polynomial Degree: f(x)=x2+10,201f(x) = x^2 + 10,201 has a degree of 22, so it has 22 roots.
  2. Conjugate Root Theorem: If 101101 is a root, then by the conjugate root theorem, the other root is 101-101 since the polynomial has real coefficients.
  3. Check Roots: Check the roots by plugging them into the polynomial:\newlinef(101)=1012+10,201=10,201+10,201=20,402f(101) = 101^2 + 10,201 = 10,201 + 10,201 = 20,402, which is not 00. Oops, there's a mistake here.

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