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10^(@),/_MBA=20^(@),/_MAC=10^(@) si 
/_MCA=30^(@). Denonstrati el triungtial ARC este inowert.

10,MBA=20,MAC=10 10^{\circ}, \angle M B A=20^{\circ}, \angle M A C=10^{\circ} si MCA=30 \angle M C A=30^{\circ} . Denonstrati el triungtial ARC este inowert.

Full solution

Q. 10,MBA=20,MAC=10 10^{\circ}, \angle M B A=20^{\circ}, \angle M A C=10^{\circ} si MCA=30 \angle M C A=30^{\circ} . Denonstrati el triungtial ARC este inowert.
  1. Find Angles of Triangle ARC: Find the angles of triangle ARC using the given information.\newlineGiven: MBA=20\angle MBA = 20^\circ, MAC=10\angle MAC = 10^\circ, and MCA=30\angle MCA = 30^\circ.\newlineSince MBA and MAC are angles at point M, their sum will give angle BAC.\newlineBAC=MBA+MAC=20+10=30\angle BAC = \angle MBA + \angle MAC = 20^\circ + 10^\circ = 30^\circ.
  2. Calculate Third Angle: Now, we know two angles of triangle ARC: BAC=30\angle BAC = 30^\circ and MCA=30\angle MCA = 30^\circ. The third angle ACR\angle ACR can be found by knowing that the sum of angles in a triangle is 180180^\circ. ACR=180(BAC+MCA)=180(30+30)=18060=120\angle ACR = 180^\circ - (\angle BAC + \angle MCA) = 180^\circ - (30^\circ + 30^\circ) = 180^\circ - 60^\circ = 120^\circ.
  3. Check for Isosceles Triangle: Check if any two angles are equal to determine if the triangle is isosceles. BAC=30\angle BAC = 30^\circ, MCA=30\angle MCA = 30^\circ, and ACR=120\angle ACR = 120^\circ. Since BAC\angle BAC and MCA\angle MCA are equal, triangle ARC is isosceles.

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