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10(9)/(y(y+3))-(y)/(y+3)=
A 
(9+y^(2))/(y(y+3))
C 
(3-y)/(y)
B 
(9-y)/(y+3)
D 
(3+y)/(y)

109y(y+3)yy+3= 10 \frac{9}{y(y+3)}-\frac{y}{y+3}= \newlineA 9+y2y(y+3) \frac{9+y^{2}}{y(y+3)} \newlineC 3yy \frac{3-y}{y} \newlineB 9yy+3 \frac{9-y}{y+3} \newlineD 3+yy \frac{3+y}{y}

Full solution

Q. 109y(y+3)yy+3= 10 \frac{9}{y(y+3)}-\frac{y}{y+3}= \newlineA 9+y2y(y+3) \frac{9+y^{2}}{y(y+3)} \newlineC 3yy \frac{3-y}{y} \newlineB 9yy+3 \frac{9-y}{y+3} \newlineD 3+yy \frac{3+y}{y}
  1. Combine terms over common denominator: Combine the terms over a common denominator, which is y(y+3)y(y+3).10(9)y(y+3)yy+3=90y(y+3)y2+3yy(y+3)\frac{10(9)}{y(y+3)} - \frac{y}{y+3} = \frac{90}{y(y+3)} - \frac{y^2 + 3y}{y(y+3)}
  2. Simplify numerator by combining like terms: Simplify the numerator by combining like terms. (90)/(y(y+3))(y2+3y)/(y(y+3))=(90y23y)/(y(y+3))(90)/(y(y+3)) - (y^2 + 3y)/(y(y+3)) = (90 - y^2 - 3y)/(y(y+3))
  3. Factor out 1-1 from terms: Factor out a 1-1 from the terms in the numerator that include yy.\newline(90y23y)/(y(y+3))=(90(y2+3y))/(y(y+3))(90 - y^2 - 3y)/(y(y+3)) = (90 - (y^2 + 3y))/(y(y+3))
  4. Recognize expression cannot be simplified further: Recognize that the expression cannot be further simplified to match any of the answer choices.