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10(5)/(9)-1(7)/(32)*(4(14)/(15)+3(1)/(15))=

1059−1732⋅(41415+3115)= 10 \frac{5}{9}-1 \frac{7}{32} \cdot\left(4 \frac{14}{15}+3 \frac{1}{15}\right)=

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Full solution

Q. 1059−1732⋅(41415+3115)= 10 \frac{5}{9}-1 \frac{7}{32} \cdot\left(4 \frac{14}{15}+3 \frac{1}{15}\right)=
  1. Simplify Expression: Step 11: Simplify the expression inside the parentheses. \newline4(1415)+3(115)=4+3=74\left(\frac{14}{15}\right) + 3\left(\frac{1}{15}\right) = 4 + 3 = 7.
  2. Multiply by −1-1: Step 22: Multiply the simplified result by −1732-1\frac{7}{32}.\newline−1732×7=−7732=−4932-1\frac{7}{32} \times 7 = -7\frac{7}{32} = -\frac{49}{32}.
  3. Subtract from 1010: Step 33: Subtract the result from 10(59)10\left(\frac{5}{9}\right). \newline10(59)−(−4932)=959+4932.10\left(\frac{5}{9}\right) - \left(-\frac{49}{32}\right) = \frac{95}{9} + \frac{49}{32}.
  4. Find Common Denominator: Step 44: Find a common denominator and add the fractions.\newlineCommon denominator of 99 and 3232 is 288288.\newline(959)⋅(3232)+(4932)⋅(99)=3040288+441288=3481288.(\frac{95}{9})\cdot(\frac{32}{32}) + (\frac{49}{32})\cdot(\frac{9}{9}) = \frac{3040}{288} + \frac{441}{288} = \frac{3481}{288}.

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