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Let’s check out your problem:
10
(
−
4
d
+
11
)
=
3
d
+
8
10(-4d+11)=3d+8
10
(
−
4
d
+
11
)
=
3
d
+
8
View step-by-step help
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Math Problems
Algebra 2
Add, subtract, multiply, and divide polynomials
Full solution
Q.
10
(
−
4
d
+
11
)
=
3
d
+
8
10(-4d+11)=3d+8
10
(
−
4
d
+
11
)
=
3
d
+
8
Distribute Terms:
Distribute
10
10
10
to each term inside the parentheses.
\newline
10
(
−
4
d
+
11
)
=
−
40
d
+
110
10(-4d + 11) = -40d + 110
10
(
−
4
d
+
11
)
=
−
40
d
+
110
Write Equation:
Write the equation with the distributed terms.
\newline
−
40
d
+
110
=
3
d
+
8
-40d + 110 = 3d + 8
−
40
d
+
110
=
3
d
+
8
Move D Terms:
Move all
d
d
d
terms to one side by adding
40
d
40d
40
d
to both sides.
\newline
−
40
d
+
40
d
+
110
=
3
d
+
40
d
+
8
-40d + 40d + 110 = 3d + 40d + 8
−
40
d
+
40
d
+
110
=
3
d
+
40
d
+
8
\newline
−
40
d
+
40
d
=
0
-40d + 40d = 0
−
40
d
+
40
d
=
0
, so the equation simplifies to:
\newline
110
=
43
d
+
8
110 = 43d + 8
110
=
43
d
+
8
Isolate D:
Isolate
d
d
d
by subtracting
8
8
8
from both sides.
\newline
110
−
8
=
43
d
110 - 8 = 43d
110
−
8
=
43
d
\newline
102
=
43
d
102 = 43d
102
=
43
d
Solve for D:
Solve for
d
d
d
by dividing both sides by
43
43
43
.
102
43
=
d
\frac{102}{43} = d
43
102
=
d
d
≈
2.372
d \approx 2.372
d
≈
2.372
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