Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

1-(sin^(2)theta)/(1-cos theta)=-cos theta

1sin2θ1cosθ=cosθ 1-\frac{\sin ^{2} \theta}{1-\cos \theta}=-\cos \theta

Full solution

Q. 1sin2θ1cosθ=cosθ 1-\frac{\sin ^{2} \theta}{1-\cos \theta}=-\cos \theta
  1. Use Pythagorean Identity: Express sin2(θ)\sin^2(\theta) using the Pythagorean identity: sin2(θ)=1cos2(θ)\sin^2(\theta) = 1 - \cos^2(\theta).
  2. Substitute sin2(θ)\sin^2(\theta): Substitute sin2(θ)\sin^2(\theta) with 1cos2(θ)1 - \cos^2(\theta) in the given expression to get 11cos2(θ)1cos(θ)1 - \frac{1 - \cos^2(\theta)}{1 - \cos(\theta)}.
  3. Simplify numerator: Simplify the numerator of the fraction: 1(1cos2(θ))1 - (1 - \cos^2(\theta)) becomes cos2(θ)\cos^2(\theta).
  4. Factor out cos(θ)\cos(\theta): Now we have 1cos2(θ)1cos(θ)\frac{1 - \cos^2(\theta)}{1 - \cos(\theta)}. Factor cos(θ)\cos(\theta) out of the numerator to get cos(θ)\cos(\theta)(cos(θ)1cos(θ))\left(\frac{\cos(\theta)}{1 - \cos(\theta)}\right).
  5. Cancel out cos(θ)\cos(\theta): Cancel out a cos(θ)\cos(\theta) from the numerator and denominator to get 1cos(θ)1 - \cos(\theta).

More problems from Simplify expressions using trigonometric identities