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1] log_(7)49=2

11] log⁡749=2 \log _{7} 49=2

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Q. 11] log⁡749=2 \log _{7} 49=2
  1. Identify Base and Number: Identify the base of the logarithm and the number whose logarithm is to be found.\newlineIn log⁡749\log_{7}49, 77 is the base and 4949 is the number.\newlineRewrite 4949 as a power of 77.\newline49=7×749 = 7 \times 7\newline49=7249 = 7^2
  2. Rewrite Number as Power: We found: 49=7249 = 7^2\newlineNow, log⁡749\log_{7}49 becomes log⁡772\log_{7}7^2.\newlineEvaluate log⁡772\log_{7}7^2.\newlineWhen the base of the logarithm matches the base of the exponent, the logarithm is equal to the exponent.\newlinelog⁡772=2\log_{7}7^2 = 2

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