Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

1 Hypotenuse of a triangle is ' 
b '. Find the maximum area of the triangle.

11 Hypotenuse of a triangle is ' b b '. Find the maximum area of the triangle.

Full solution

Q. 11 Hypotenuse of a triangle is ' b b '. Find the maximum area of the triangle.
  1. Triangle Construction: To find the maximum area of a triangle with a given hypotenuse, we can use a right-angled triangle where the two legs are equal, because this will give us the maximum area. The legs will each be b2\frac{b}{\sqrt{2}} long.\newlineCalculation: Legs = b2\frac{b}{\sqrt{2}}
  2. Area Calculation: Now, we use the formula for the area of a triangle, which is 12×base×height\frac{1}{2} \times \text{base} \times \text{height}. Since our triangle is right-angled and the legs are equal, the base and height are both 'b2\frac{b}{\sqrt{2}}'.\newlineCalculation: Area = 12×(b2)×(b2)\frac{1}{2} \times \left(\frac{b}{\sqrt{2}}\right) \times \left(\frac{b}{\sqrt{2}}\right)
  3. Area Simplification: Simplify the area formula by multiplying the base and height and then multiplying by 12\frac{1}{2}.\newlineCalculation: Area = 12×(b22)\frac{1}{2} \times \left(\frac{b^2}{2}\right)

More problems from Area of quadrilaterals and triangles: word problems