Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

1.] A particle is moving along a horizontal line and the velocity of the particle is given at various times in the table below.





t(hr)
1
4
9
10



v(t)(m//hr)
3
7
12
7




Is there a time 
c,4 < c < 10, such that 
a(c)=0 ? Explain your reasoning.

11.] A particle is moving along a horizontal line and the velocity of the particle is given at various times in the table below.\newline\begin{tabular}{|c|c|c|c|c|}\newline\hline t(hr) \mathrm{t}(\mathrm{hr}) & 11 & 44 & 99 & 1010 \\\newline\hline v(t)(m/hr) \mathrm{v}(\mathrm{t})(\mathrm{m} / \mathrm{hr}) & 33 & 77 & 1212 & 77 \\\newline\hline\newline\end{tabular}\newlineIs there a time c,4<c<10 \mathrm{c}, 4<c<10 , such that a(c)=0 \mathrm{a}(\mathrm{c})=0 ? Explain your reasoning.

Full solution

Q. 11.] A particle is moving along a horizontal line and the velocity of the particle is given at various times in the table below.\newline\begin{tabular}{|c|c|c|c|c|}\newline\hline t(hr) \mathrm{t}(\mathrm{hr}) & 11 & 44 & 99 & 1010 \\\newline\hline v(t)(m/hr) \mathrm{v}(\mathrm{t})(\mathrm{m} / \mathrm{hr}) & 33 & 77 & 1212 & 77 \\\newline\hline\newline\end{tabular}\newlineIs there a time c,4<c<10 \mathrm{c}, 4<c<10 , such that a(c)=0 \mathrm{a}(\mathrm{c})=0 ? Explain your reasoning.
  1. Identify Time Interval: To find if there's a time cc where the acceleration a(c)=0a(c) = 0, we need to look at the changes in velocity over the time intervals.
  2. Velocity Changes Analysis: Between t=4t = 4 and t=9t = 9, the velocity increases from 77 m/hr to 1212 m/hr. This means the particle is accelerating.
  3. Acceleration Determination: Between t=9t = 9 and t=10t = 10, the velocity decreases from 12m/hr12 \, \text{m/hr} to 7m/hr7 \, \text{m/hr}. This means the particle is decelerating.
  4. Acceleration Change Conclusion: If the velocity increases and then decreases, there must be a point where the acceleration changes from positive to negative, which means there is a point where the acceleration is 00.
  5. Existence of Zero Acceleration: Therefore, there is a time cc, where 4<c<104 < c < 10, such that the acceleration a(c)=0a(c) = 0.

More problems from Probability of independent and dependent events