1.] A particle is moving along a horizontal line and the velocity of the particle is given at various times in the table below.\begin{tabular}{|c|c|c|c|c|}\hline t(hr) & 1 & 4 & 9 & 10 \\\hline v(t)(m/hr) & 3 & 7 & 12 & 7 \\\hline\end{tabular}Is there a time c,4<c<10, such that a(c)=0 ? Explain your reasoning.
Q. 1.] A particle is moving along a horizontal line and the velocity of the particle is given at various times in the table below.\begin{tabular}{|c|c|c|c|c|}\hline t(hr) & 1 & 4 & 9 & 10 \\\hline v(t)(m/hr) & 3 & 7 & 12 & 7 \\\hline\end{tabular}Is there a time c,4<c<10, such that a(c)=0 ? Explain your reasoning.
Identify Time Interval: To find if there's a time c where the acceleration a(c)=0, we need to look at the changes in velocity over the time intervals.
Velocity Changes Analysis: Between t=4 and t=9, the velocity increases from 7 m/hr to 12 m/hr. This means the particle is accelerating.
Acceleration Determination: Between t=9 and t=10, the velocity decreases from 12m/hr to 7m/hr. This means the particle is decelerating.
Acceleration Change Conclusion: If the velocity increases and then decreases, there must be a point where the acceleration changes from positive to negative, which means there is a point where the acceleration is 0.
Existence of Zero Acceleration: Therefore, there is a time c, where 4<c<10, such that the acceleration a(c)=0.
More problems from Probability of independent and dependent events