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1.) 
{:[2,x-3y=-1],[y,=x-1]:}

11.) 2x3y=1y=x1 \begin{array}{rl}2 & x-3 y=-1 \\ y & =x-1\end{array}

Full solution

Q. 11.) 2x3y=1y=x1 \begin{array}{rl}2 & x-3 y=-1 \\ y & =x-1\end{array}
  1. Solve for y: Solve the second equation for y:\newliney=x1y = x - 1
  2. Substitute into first equation: Substitute y=x1y = x - 1 into the first equation: 2x3(x1)=12x - 3(x - 1) = -1
  3. Distribute and combine terms: Distribute and combine like terms:\newline2x3x+3=12x - 3x + 3 = -1\newlinex+3=1-x + 3 = -1
  4. Solve for x: Solve for x:\newlinex+3=1-x + 3 = -1\newlinex=13-x = -1 - 3\newlinex=4-x = -4\newlinex=4x = 4

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