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0.5(8w+2v)=3

8w=2-v+4w
Which of the following accurately describes all solutions to the system of equations shown?
Choose 1 answer:
(A) 
v=1 and 
w=(1)/(4)
(B) 
v=4 and 
w=-(1)/(4)
(c) There are infinite solutions to the system.
(D) There are no solutions to the system.

0.5(8w+2v)=3 0.5(8 w+2 v)=3 \newline8w=2v+4w 8 w=2-v+4 w \newlineWhich of the following accurately describes all solutions to the system of equations shown?\newlineChoose 11 answer:\newline(A) v=1 v=1 and w=14 w=\frac{1}{4} \newline(B) v=4 v=4 and w=14 w=-\frac{1}{4} \newline(C) There are infinite solutions to the system.\newline(D) There are no solutions to the system.

Full solution

Q. 0.5(8w+2v)=3 0.5(8 w+2 v)=3 \newline8w=2v+4w 8 w=2-v+4 w \newlineWhich of the following accurately describes all solutions to the system of equations shown?\newlineChoose 11 answer:\newline(A) v=1 v=1 and w=14 w=\frac{1}{4} \newline(B) v=4 v=4 and w=14 w=-\frac{1}{4} \newline(C) There are infinite solutions to the system.\newline(D) There are no solutions to the system.
  1. Simplify Equation 11: Simplify the first equation.\newlineGiven the equation 0.5(8w+2v)=30.5(8w+2v)=3, distribute the 0.50.5 to both terms inside the parentheses.\newline0.5×8w+0.5×2v=30.5 \times 8w + 0.5 \times 2v = 3\newline4w+v=34w + v = 3
  2. Simplify Equation 22: Simplify the second equation.\newlineGiven the equation 8w=2v+4w8w = 2 - v + 4w, subtract 4w4w from both sides to isolate the terms with ww on one side.\newline8w4w=2v8w - 4w = 2 - v\newline4w=2v4w = 2 - v
  3. Compare Simplified Equations: Compare the two simplified equations.\newlineWe have 4w+v=34w + v = 3 from Step 11 and 4w=2v4w = 2 - v from Step 22. Notice that both equations have 4w4w as a term. We can set them equal to each other to find the relationship between vv and ww.\newline4w+v=4wv+24w + v = 4w - v + 2
  4. Solve for v: Solve for v.\newlineSubtract 4w4w from both sides of the equation.\newlinev=v+2v = -v + 2\newlineAdd vv to both sides to get all vv terms on one side.\newline2v=22v = 2\newlineDivide both sides by 22 to solve for v.\newlinev=1v = 1
  5. Substitute and Solve for ww: Substitute v=1v = 1 into one of the simplified equations to solve for ww. Using the equation from Step 11: 4w+v=34w + v = 3, substitute v=1v = 1. 4w+1=34w + 1 = 3 Subtract 11 from both sides. 4w=24w = 2 Divide both sides by 44. w=0.5w = 0.5

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