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Let’s check out your problem:

(z+1)/(z-2)=(z+8)/(z-4)

z+1z−2=z+8z−4 \frac{z+1}{z-2}=\frac{z+8}{z-4}

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Add, subtract, multiply, and divide polynomialsright chevron icon

Full solution

Q. z+1z−2=z+8z−4 \frac{z+1}{z-2}=\frac{z+8}{z-4}
  1. Expand Equation: Expand both sides of the equation. z2−4z+z−4=z2+8z−2z−16z^2 - 4z + z - 4 = z^2 + 8z - 2z - 16
  2. Combine Like Terms: Combine like terms. z2−3z−4=z2+6z−16z^2 - 3z - 4 = z^2 + 6z - 16
  3. Subtract z2z^2: Subtract z2z^2 from both sides to get rid of the z2z^2 term.\newline−3z−4=6z−16-3z - 4 = 6z - 16
  4. Add 3z3z: Add 3z3z to both sides to move the z terms to one side.\newline−4=9z−16-4 = 9z - 16
  5. Add 1616: Add 1616 to both sides to isolate the zz term.\newline12=9z12 = 9z
  6. Divide by 99: Divide both sides by 99 to solve for zz.z=129z = \frac{12}{9}
  7. Simplify Fraction: Simplify the fraction. z=43z = \frac{4}{3}

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