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{:[y=-5x+1],[y=3x-2]:}
Is 
(3,8) a solution of the system?
Choose 1 answer:
(A) Yes
(B) 
No

y=5x+1y=3x2 \begin{array}{l} y=-5 x+1 \\ y=3 x-2 \end{array} \newlineIs (3,8) (3,8) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. y=5x+1y=3x2 \begin{array}{l} y=-5 x+1 \\ y=3 x-2 \end{array} \newlineIs (3,8) (3,8) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substituting point into first equation: First, we will substitute the point (3,8)(3,8) into the first equation and check if it holds true. The first equation is y=5x+1y = -5x + 1. If we substitute x=3x=3 and y=8y=8, we get 8=53+18 = -5 \cdot 3 + 1.
  2. Checking if the equation holds true: After performing the calculation, we find that 8=15+18 = -15 + 1, which simplifies to 8=148 = -14. This is not true. Therefore, the point (3,8)(3,8) does not satisfy the first equation.
  3. Conclusion: Point does not satisfy first equation: Since the point (3,8)(3,8) does not satisfy the first equation, there is no need to check the second equation. The point (3,8)(3,8) cannot be a solution to the system if it does not satisfy both equations.

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