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{:[y=-4x+6],[3x+4y=-2]:}
Is 
(2,2) a solution of the system?
Choose 1 answer:
(A) Yes
(B) 
No

y=4x+6 y=-4 x+6 \newline3x+4y=2 3 x+4 y=-2 \newlineIs (2,2) (2,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. y=4x+6 y=-4 x+6 \newline3x+4y=2 3 x+4 y=-2 \newlineIs (2,2) (2,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substituting point into first equation: First, we will substitute the point (2,2)(2,2) into the first equation and check if it holds true. The first equation is y=4x+6y = -4x + 6. If we substitute x=2x=2 and y=2y=2, we get 2=42+62 = -4 \cdot 2 + 6.
  2. Checking if equation holds true: After performing the calculation, we find that 2=8+62 = -8 + 6, which simplifies to 2=22 = -2. This is not true. Therefore, the point (2,2)(2,2) does not satisfy the first equation.
  3. Conclusion: Point does not satisfy first equation: Since the point (2,2)(2,2) does not satisfy the first equation, there is no need to check the second equation. The point (2,2)(2,2) cannot be a solution to the system of equations if it does not satisfy both equations.

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