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{:[y=-4x-5],[y=3x-2]:}
Is 
(3,7) a solution of the system?
Choose 1 answer:
(A) Yes
(B) 
No

y=4x5 y=-4 x-5 \newliney=3x2 y=3 x-2 \newlineIs (3,7) (3,7) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. y=4x5 y=-4 x-5 \newliney=3x2 y=3 x-2 \newlineIs (3,7) (3,7) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substituting point into first equation: First, we will substitute the point (3,7)(3,7) into the first equation and check if it holds true. The first equation is y=4x5y = -4x - 5. If we substitute x=3x=3 and y=7y=7, we get 7=4357 = -4 \cdot 3 - 5.
  2. Checking if first equation holds true: After performing the calculation, we find that 7=1257 = -12 - 5, which simplifies to 7=177 = -17. This is not true. Therefore, the point (3,7)(3,7) does not satisfy the first equation.
  3. Conclusion: Point does not satisfy first equation: Since the point (3,7)(3,7) does not satisfy the first equation, there is no need to check the second equation. The point (3,7)(3,7) cannot be a solution to the system of equations if it does not satisfy both equations.

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