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如图, 在平面直角坐标系 
xOy 中, 直线 
l_(1) 经过 
O(0,0)、A(1,2) 两点, 将直线 
l_(1) 向下平移 6 个单位得到直线 
l_(2), 交 
x 轴于点 
C,B 是直线 
l_(2)上一点, 且四边形 
ABCO 是平行四边形.
(1)求直线 
l_(2) 的表达式及 
B 点的坐标;
(2) 若 
D 是平面直角坐标系内的一点, 且以 
O

A、C、D 四个点为顶点的四边形是等腰梯形, 求点 
D 的坐标.

如图, 在平面直角坐标系 xOy x O y 中, 直线 l1 l_{1} 经过 O(0,0)A(1,2) O(0,0) 、 A(1,2) 两点, 将直线 l1 l_{1} 向下平移 66 个单位得到直线 l2 l_{2} , 交 x x 轴于点 C,B C, B 是直线 l2 l_{2} 上一点, 且四边形 ABCO A B C O 是平行四边形.\newline11)求直线 l2 l_{2} 的表达式及 l1 l_{1} 00 点的坐标;\newline(22) 若 l1 l_{1} 11 是平面直角坐标系内的一点, 且以 l1 l_{1} 22\newlinel1 l_{1} 33 四个点为顶点的四边形是等腰梯形, 求点 l1 l_{1} 11 的坐标.

Full solution

Q. 如图, 在平面直角坐标系 xOy x O y 中, 直线 l1 l_{1} 经过 O(0,0)A(1,2) O(0,0) 、 A(1,2) 两点, 将直线 l1 l_{1} 向下平移 66 个单位得到直线 l2 l_{2} , 交 x x 轴于点 C,B C, B 是直线 l2 l_{2} 上一点, 且四边形 ABCO A B C O 是平行四边形.\newline11)求直线 l2 l_{2} 的表达式及 l1 l_{1} 00 点的坐标;\newline(22) 若 l1 l_{1} 11 是平面直角坐标系内的一点, 且以 l1 l_{1} 22\newlinel1 l_{1} 33 四个点为顶点的四边形是等腰梯形, 求点 l1 l_{1} 11 的坐标.
  1. Find Slope of Line: Find the slope of line l1l_{1} using points O(0,0)O(0,0) and A(1,2)A(1,2).\ Slope (m)=y2y1x2x1=2010=2(m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 0}{1 - 0} = 2.\ Equation of l1l_{1} using slope-intercept form: y=mx+cy = mx + c. Since it passes through the origin, c=0c = 0.\ Equation of l1l_{1}: y=2xy = 2x.
  2. Shift Line Downward: Derive the equation of line l2l_{2} by shifting l1l_{1} downward by 66 units.\newlineNew y-intercept = original y-intercept 6=06=6- 6 = 0 - 6 = -6.\newlineEquation of l2l_{2}: y=2x6y = 2x - 6.
  3. Find X-Intercept: Find the x-intercept of l2l_{2} where y=0y = 0.\newline0=2x60 = 2x - 6; 2x=62x = 6; x=3x = 3.\newlinePoint C on l2l_{2} and x-axis: C(3,0)C(3,0).
  4. Parallelogram Property: Since ABCOABCO is a parallelogram, vectors OAOA and BCBC are parallel and equal, and vectors ABAB and OCOC are also.\newlineCoordinates of BB can be found using vector addition: B=CA+OB = C - A + O.\newlineB=(3,0)(1,2)+(0,0)=(2,2)B = (3,0) - (1,2) + (0,0) = (2,-2).\newlineThis is incorrect, let's correct it: B=(3,0)(0,0)+(1,2)=(4,2)B = (3,0) - (0,0) + (1,2) = (4,2).

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