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{:[-x+4y=-9],[y=-2x+6]:} Is (2,3) a solution of the system? Choose 1 answer: (A) Yes (B) No

−x+4y=−9 -x+4 y=-9 \newliney=−2x+6 y=-2 x+6 \newlineIs (2,3) (2,3) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

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Full solution

Q. −x+4y=−9 -x+4 y=-9 \newliney=−2x+6 y=-2 x+6 \newlineIs (2,3) (2,3) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitute and check first equation: First, we will substitute the point (2,3)(2,3) into the first equation and check if it holds true. The first equation is −x+4y=−9-x + 4y = -9. If we substitute x=2x=2 and y=3y=3, we get −2+4×3=−9-2 + 4\times3 = -9.
  2. Result of first equation substitution: After performing the calculation, we find that −2+12=10-2 + 12 = 10, which is not equal to −9-9. Therefore, the point (2,3)(2,3) does not satisfy the first equation.
  3. No need to check second equation: Since the point (2,3)(2,3) does not satisfy the first equation, there is no need to check the second equation. The point (2,3)(2,3) is not a solution to the system of equations.

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