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(x+3)/(5)=(2x+3)/(9)

x+35=2x+39 \frac{x+3}{5}=\frac{2 x+3}{9}

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Q. x+35=2x+39 \frac{x+3}{5}=\frac{2 x+3}{9}
  1. Cross-Multiply Fractions: Cross-multiply to eliminate the fractions.\newlinex+35=2x+39\frac{x + 3}{5} = \frac{2x + 3}{9}\newlineCross-multiplying gives us:\newline9(x+3)=5(2x+3)9(x + 3) = 5(2x + 3)
  2. Distribute Numbers: Distribute the numbers on both sides.\newline9×x+9×3=5×2x+5×39 \times x + 9 \times 3 = 5 \times 2x + 5 \times 3\newline9x+27=10x+159x + 27 = 10x + 15
  3. Move Terms: Move the terms involving xx to one side and constant terms to the other side.\newlineSubtract 9x9x from both sides:\newline9x+279x=10x+159x9x + 27 - 9x = 10x + 15 - 9x\newlineThis simplifies to:\newline27=x+1527 = x + 15
  4. Isolate x: Isolate x by subtracting 1515 from both sides.\newline2715=x+151527 - 15 = x + 15 - 15\newlineThis simplifies to:\newline12=x12 = x

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