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$(x + 3)^2 - 4 = 0$

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Powers with decimal and fractional bases

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Q.

(x + 3)^2 - 4 = 0

Isolate squared term: Isolate the squared term. $\newline$ We need to isolate the squared term $(x + 3)^2$ by moving the constant term to the other side of the equation. $\newline$ $(x + 3)^2 - 4 = 0$ $\newline$ Add $4$ to both sides to isolate the squared term. $\newline$ $(x + 3)^2 = 4$
Take square root: Take the square root of both sides. $\newline$ To solve for $x$ , we need to take the square root of both sides of the equation. $\newline$ $\sqrt{(x + 3)^2} = \pm\sqrt{4}$ $\newline$ This gives us two possible solutions for $x + 3$ . $\newline$ $x + 3 = \pm2$
Solve for x: Solve for x. $\newline$ We now have two equations to solve for x: $\newline$ $1$ ) $x + 3 = 2$ $\newline$ $2$ ) $x + 3 = -2$ $\newline$ For the first equation: $\newline$ $x + 3 = 2$ $\newline$ Subtract $3$ from both sides to solve for x. $\newline$ $x = 2 - 3$ $\newline$ $x = -1$ $\newline$ For the second equation: $\newline$ $x + 3 = -2$ $\newline$ Subtract $3$ from both sides to solve for x. $\newline$ $x = -2 - 3$ $\newline$ $x = -5$

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