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(x^(2)+3x-a)/(x-2)=x+5
(iiven the equation for all
x!=2, what is the value of
a

$\frac{x^{2}+3 x-a}{x-2}=x+5$ $\newline$ (iiven the equation for all $x \neq 2$ , what is the value of $a$

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Evaluate expression when two complex numbers are given

Full solution

Q.

\frac{x^{2}+3 x-a}{x-2}=x+5

\newline

(iiven the equation for all

x \neq 2

, what is the value of

a

Given Equation: We are given the equation: $\newline$ $(x^{2}+3x-a)/(x-2)=x+5$ $\newline$ We need to find the value of $a$ . To do this, we will multiply both sides of the equation by $(x-2)$ to eliminate the denominator. $\newline$ $(x^{2}+3x-a) = (x+5)(x-2)$
Eliminate Denominator: Now we will expand the right side of the equation: $\newline$ $(x+5)(x-2) = x^2 - 2x + 5x - 10$ $\newline$ Simplify the terms: $\newline$ $x^2 + 3x - 10$
Expand Right Side: Next, we will compare the coefficients from the left side of the equation to the right side: $\newline$ $x^2 + 3x - a = x^2 + 3x - 10$ $\newline$ Since the $x^2$ and $3x$ terms are identical on both sides, we can equate the constants to find the value of $a$ : $\newline$ $-a = -10$
Compare Coefficients: Finally, we solve for $a$ : $a = 10$

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