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(x-12)+y+z? for 
x=-23,y=-5, and 
z=-10

11. (x12)+y+z? (x-12)+y+z ? for x=23,y=5 x=-23, y=-5 , and z=10 z=-10

Full solution

Q. 11. (x12)+y+z? (x-12)+y+z ? for x=23,y=5 x=-23, y=-5 , and z=10 z=-10
  1. Substitute Values: First, substitute the given values into the expression.\newlineCalculation: (2312)+(5)+(10)(-23-12)+(-5)+(-10)
  2. Add Numbers in Parentheses: Now, add the numbers inside the parentheses.\newlineCalculation: 35510-35-5-10
  3. Add All Numbers Together: Finally, add all the numbers together.\newlineCalculation: 35510=50-35-5-10 = -50

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