Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

{:[x_(1)+x_(1)+2x_(3)=-1],[x_(1)-2x_(2)+x_(3)=-5],[3x_(1)+x_(2)+x_(3)=3]:}
Find all solutions by using the Guassian
elimination and Gauss-Jordan Reduction

x1+x1+2x3=1x12x2+x3=53x1+x2+x3=3 \begin{array}{l} x_{1}+x_{1}+2 x_{3}=-1 \\ x_{1}-2 x_{2}+x_{3}=-5 \\ 3 x_{1}+x_{2}+x_{3}=3 \end{array} \newlineFind all solutions by using the Guassian\newlineelimination and Gauss-Jordan Reduction

Full solution

Q. x1+x1+2x3=1x12x2+x3=53x1+x2+x3=3 \begin{array}{l} x_{1}+x_{1}+2 x_{3}=-1 \\ x_{1}-2 x_{2}+x_{3}=-5 \\ 3 x_{1}+x_{2}+x_{3}=3 \end{array} \newlineFind all solutions by using the Guassian\newlineelimination and Gauss-Jordan Reduction
  1. Write Augmented Matrix: Write down the augmented matrix for the system of equations.\newline[102112153113] \begin{bmatrix} 1 & 0 & 2 & | & -1 \\ 1 & -2 & 1 & | & -5 \\ 3 & 1 & 1 & | & 3 \end{bmatrix}
  2. Perform Gaussian Elimination Step 11: Perform the first step of Gaussian elimination: Make the first element of the first column a 11 (already done) and use it to make all elements below it in the same column 00.\newlineSubtract the first row from the second row:\newline[102102143113] \begin{bmatrix} 1 & 0 & 2 & | & -1 \\ 0 & -2 & -1 & | & -4 \\ 3 & 1 & 1 & | & 3 \end{bmatrix} \newlineSubtract 33 times the first row from the third row:\newline[102102140156] \begin{bmatrix} 1 & 0 & 2 & | & -1 \\ 0 & -2 & -1 & | & -4 \\ 0 & 1 & -5 & | & 6 \end{bmatrix}
  3. Make Second Element 11: Next, make the second element of the second column a 11 by dividing the second row by 2-2.\newline[1021010.520156] \begin{bmatrix} 1 & 0 & 2 & | & -1 \\ 0 & 1 & 0.5 & | & 2 \\ 0 & 1 & -5 & | & 6 \end{bmatrix} \newlineThen, use the second row to make all elements above and below it in the same column 00.\newlineAdd the second row to the third row:\newline[1021010.52004.58] \begin{bmatrix} 1 & 0 & 2 & | & -1 \\ 0 & 1 & 0.5 & | & 2 \\ 0 & 0 & -4.5 & | & 8 \end{bmatrix}
  4. Make Third Element 11: Finally, make the third element of the third column a 11 by dividing the third row by 4-4.55.\newline[1021010.520011.777] \begin{bmatrix} 1 & 0 & 2 & | & -1 \\ 0 & 1 & 0.5 & | & 2 \\ 0 & 0 & 1 & | & -1.777\ldots \end{bmatrix} \newlineThen, use the third row to make all elements above it in the same column 00.\newlineSubtract 22 times the third row from the first row and subtract 00.55 times the third row from the second row:\newline[1002.5550103.1110011.777] \begin{bmatrix} 1 & 0 & 0 & | & 2.555\ldots \\ 0 & 1 & 0 & | & 3.111\ldots \\ 0 & 0 & 1 & | & -1.777\ldots \end{bmatrix}