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Let’s check out your problem:

(x+1)/(2)=(x+3)/(3)

x+12=x+33 \frac{x+1}{2}=\frac{x+3}{3}

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Full solution

Q. x+12=x+33 \frac{x+1}{2}=\frac{x+3}{3}
  1. Cross-multiply fractions: Cross-multiply to eliminate the fractions.\newline(x+1)/2=(x+3)/3(x + 1)/2 = (x + 3)/3\newlineCross-multiplying gives us:\newline3(x+1)=2(x+3)3(x + 1) = 2(x + 3)
  2. Distribute numbers: Distribute the numbers outside the parentheses.\newline3(x+1)=2(x+3)3(x + 1) = 2(x + 3)\newline3x+3=2x+63x + 3 = 2x + 6
  3. Subtract xx terms: Subtract 2x2x from both sides to get the xx terms on one side.\newline3x+3−2x=2x+6−2x3x + 3 - 2x = 2x + 6 - 2x\newlinex+3=6x + 3 = 6
  4. Solve for x: Subtract 33 from both sides to solve for xx.\newlinex+3−3=6−3x + 3 - 3 = 6 - 3\newlinex=3x = 3

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