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Unit 7 Homework
Question 10 of 20 (1 point) | Question Attempt: 1 of Unlimited
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Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.
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\therefore www-awu.aleks.com/alekscgi/x/Isl.exe/1010_u-IgNsIkr77j88P33jH-IBluonLF77GsfmBxLWEUDiYeCmloA55WJ33\newlineUnit 77 Homework\newlineQuestion 1010 of 2020 (11 point) | Question Attempt: 11 of Unlimited\newline66\newline77\newline88\newline9 \checkmark 9 \newline1010\newline1111\newline1212\newline1313\newlineThree vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.\newlineCheck

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Q. \therefore www-awu.aleks.com/alekscgi/x/Isl.exe/1010_u-IgNsIkr77j88P33jH-IBluonLF77GsfmBxLWEUDiYeCmloA55WJ33\newlineUnit 77 Homework\newlineQuestion 1010 of 2020 (11 point) | Question Attempt: 11 of Unlimited\newline66\newline77\newline88\newline9 \checkmark 9 \newline1010\newline1111\newline1212\newline1313\newlineThree vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.\newlineCheck
  1. Identify Parallelogram Properties: The parallelogram has opposite sides that are equal and parallel. We can use the given three vertices to find the fourth by using vector addition.
  2. Find Fourth Vertex using Vector Addition: Let's say the given vertices are AA, BB, and CC, and we need to find DD. If we assume AA and CC are opposite vertices, then we can find DD by using the fact that the diagonals of a parallelogram bisect each other.
  3. Calculate Midpoint of Diagonal AC: We can calculate the midpoint MM of the diagonal ACAC, which will also be the midpoint of BDBD. Then we can use the midpoint formula M=(x1+x22,y1+y22)M = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) where (x1,y1)(x_1, y_1) are the coordinates of AA and (x2,y2)(x_2, y_2) are the coordinates of CC.
  4. Use Midpoint Formula for Coordinates of D: Let's say the coordinates of A are (x1,y1)(x_1, y_1), B are (x2,y2)(x_2, y_2), and C are (x3,y3)(x_3, y_3). We calculate the midpoint M of AC using M=(x1+x32,y1+y32)M = \left(\frac{x_1 + x_3}{2}, \frac{y_1 + y_3}{2}\right).
  5. Find Coordinates of D using Midpoint Formula: Now, we can find the coordinates of D by using the fact that M is also the midpoint of BD. So, D=(2Mxx2,2Myy2)D = (2M_x - x_2, 2M_y - y_2) where MxM_x and MyM_y are the xx and yy coordinates of M, respectively.
  6. Find Coordinates of D using Midpoint Formula: Now, we can find the coordinates of D by using the fact that M is also the midpoint of BD. So, D=(2Mxx2,2Myy2)D = (2M_x - x_2, 2M_y - y_2) where MxM_x and MyM_y are the xx and yy coordinates of M, respectively.We plug in the values of M and B into the formula for D and solve for the coordinates of D.

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