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The perimeter pp of the rectangle below is 3030 inches. Which formula can be used to find the length and width of the rectangle?\newlineA p=w+(w+3)p = w + (w + 3)\newlineB p=w(w+3)p = w(w + 3)\newlineC p=2w+2(w+3)p = 2w + 2(w + 3)\newlineD p=2(w+3)2wp = 2(w + 3) - 2w

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Q. The perimeter pp of the rectangle below is 3030 inches. Which formula can be used to find the length and width of the rectangle?\newlineA p=w+(w+3)p = w + (w + 3)\newlineB p=w(w+3)p = w(w + 3)\newlineC p=2w+2(w+3)p = 2w + 2(w + 3)\newlineD p=2(w+3)2wp = 2(w + 3) - 2w
  1. Identify Formula: Identify the correct formula for the perimeter of a rectangle.\newlineThe perimeter PP of a rectangle is given by P=2(length+width)P = 2(\text{length} + \text{width}).\newlineHere, the width is ww and the length is w+3w + 3.\newlineSo, the formula becomes P=2(w+(w+3))P = 2(w + (w + 3)).
  2. Match with Options: Match the derived formula with the given options.\newlineThe derived formula is P=2(w+w+3)=2(2w+3)P = 2(w + w + 3) = 2(2w + 3).\newlineSimplify to get P=4w+6P = 4w + 6.\newlineCompare with options:\newlineA) p=w+(w+3)p = w + (w + 3) - Incorrect, doesn't account for all sides.\newlineB) p=w(w+3)p = w(w + 3) - Incorrect, represents area, not perimeter.\newlineC) p=2w+2(w+3)p = 2w + 2(w + 3) - Correct, simplifies to 4w+64w + 6.\newlineD) p=2(w+3)2wp = 2(w + 3) – 2w - Incorrect, simplifies to 66.

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