(t+38)(t+b)=0In the given equation, b is a constant. If −38 and 313 are solutions to the equation, then what is the value of b ?Choose 1 answer:(A) −313(B) −38(C) 38(D) 313
Q. (t+38)(t+b)=0In the given equation, b is a constant. If −38 and 313 are solutions to the equation, then what is the value of b ?Choose 1 answer:(A) −313(B) −38(C) 38(D) 313
Given Equation Analysis: We are given the equation (t+38)(t+b)=0 and told that −38 and 313 are solutions to this equation. This means that when we substitute t with either −38 or 313, the equation should be satisfied.
Substitute First Solution: First, let's substitute t with the first solution −38 into the equation and see if it satisfies the equation.(t+38)(t+b)=0Substitute t=−38:((−38)+38)((−38)+b)=0
Simplify First Substitution: Simplify the expression:(0)(((8)/(3))+b)=0Since anything multiplied by 0 is 0, this part of the equation is satisfied regardless of the value of b.
Substitute Second Solution: Now, let's substitute t with the second solution 313 into the equation.(t+38)(t+b)=0Substitute t=313:((313)+38)((313)+b)=0
Simplify Second Substitution: Simplify the expression:321(313+b)=0Since 321 is 7 and 7 is not equal to 0, the only way for the product to be 0 is if the second factor is 0.
Solve for b: Set the second factor equal to zero and solve for b: (313)+b=0b=−(313)
Final Answer: We have found the value of b that satisfies the equation when t is 313. Since the problem asks for the value of b, we have our answer.