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{(sqrt(2-2)×2)-11}-7+17

{(22×2)11}7+17 \{(\sqrt{2-2} \times 2)-11\}-7+17

Full solution

Q. {(22×2)11}7+17 \{(\sqrt{2-2} \times 2)-11\}-7+17
  1. Calculate value inside square root: First, calculate the value inside the square root: 22\sqrt{2 - 2}.22=02 - 2 = 0
  2. Find square root of 00: Now, find the square root of 00: 0\sqrt{0}.\newline0=0\sqrt{0} = 0
  3. Multiply by 22: Multiply the result by 22: 0×20 \times 2.\newline0×2=00 \times 2 = 0
  4. Subtract 1111: Subtract 1111 from the result: 0110 - 11.\newline011=110 - 11 = -11
  5. Subtract 77: Subtract 77 from the result: 117-11 - 7.\newline117=18-11 - 7 = -18
  6. Add 1717: Finally, add 1717 to the result: 18+17-18 + 17. 18+17=1-18 + 17 = -1

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