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{[sin(x+pi)],[sin(x)=-0","3]:}

{sin⁡(x+π)sin⁡(x)=−0,3 \left\{\begin{array}{l}\sin (x+\pi) \\ \sin (x)=-0,3\end{array}\right.

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Full solution

Q. {sin⁡(x+π)sin⁡(x)=−0,3 \left\{\begin{array}{l}\sin (x+\pi) \\ \sin (x)=-0,3\end{array}\right.
  1. Apply identity: Use the identity sin⁡(x+π)=−sin⁡(x)\sin(x + \pi) = -\sin(x) to find sin⁡(x+π)\sin(x + \pi).\newlinesin⁡(x+π)=−sin⁡(x)\sin(x + \pi) = -\sin(x)\newlinesin⁡(x+π)=−(−0.3)\sin(x + \pi) = -(-0.3)\newlinesin⁡(x+π)=0.3\sin(x + \pi) = 0.3

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