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Simplify the trigonometric expression \newlinesinx+cotxcosx\sin x + \cot x \cos x

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Q. Simplify the trigonometric expression \newlinesinx+cotxcosx\sin x + \cot x \cos x
  1. Recognize Identities: Recognize the trigonometric identities involved.\newlineThe expression contains sinx\sin x, cotx\cot x, and cosx\cos x. We know that cotx\cot x is the reciprocal of tanx\tan x, which means cotx=1tanx\cot x = \frac{1}{\tan x} or cotx=cosxsinx\cot x = \frac{\cos x}{\sin x}.
  2. Substitute Expression: Substitute the expression for cotx\cot x in terms of sinx\sin x and cosx\cos x.sinx+cotxcosx=sinx+(cosxsinx)cosx\sin x + \cot x \cos x = \sin x + \left(\frac{\cos x}{\sin x}\right) \cos x
  3. Simplify by Multiplying: Simplify the expression by multiplying cosx\cos x with cosxsinx\frac{\cos x}{\sin x}.sinx+(cosxsinx)cosx=sinx+(cos2xsinx)\sin x + \left(\frac{\cos x}{\sin x}\right) \cos x = \sin x + \left(\frac{\cos^2 x}{\sin x}\right)
  4. Combine Terms: Combine the terms over a common denominator.\newlinesinx+cos2xsinx\sin x + \frac{\cos^2 x}{\sin x} \newline= sin2x+cos2xsinx\frac{\sin^2 x + \cos^2 x}{\sin x}
  5. Recognize Another Identity: Recognize another trigonometric identity.\newlineWe know that sin2x+cos2x=1\sin^2 x + \cos^2 x = 1, which is the Pythagorean identity for sine and cosine.
  6. Apply Pythagorean Identity: Apply the Pythagorean identity to the expression. \newline(sin2x+cos2x)/sinx=1/sinx(\sin^2 x + \cos^2 x)/\sin x = 1/\sin x
  7. Recognize Reciprocal: Recognize that 1sinx\frac{1}{\sin x} is the reciprocal of sinx\sin x, which is cscx\csc x.\newline1sinx=cscx\frac{1}{\sin x} = \csc x
  8. Write Final Expression: Write the final simplified expression.\newlineThe simplified expression is cscx\csc x.

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