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Let’s check out your problem:
(
P
−
4
)
2
=
16
(P-4)^2=16
(
P
−
4
)
2
=
16
View step-by-step help
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Math Problems
Grade 7
Powers with decimal and fractional bases
Full solution
Q.
(
P
−
4
)
2
=
16
(P-4)^2=16
(
P
−
4
)
2
=
16
Calculate square root:
Calculate the square root of
16
16
16
to find the possible values of
(
P
−
4
)
(P-4)
(
P
−
4
)
.
16
=
4
\sqrt{16} = 4
16
=
4
or
−
4
-4
−
4
Set up equations:
Set up two equations based on the square root results.
\newline
(
P
−
4
)
=
4
(P-4) = 4
(
P
−
4
)
=
4
and
(
P
−
4
)
=
−
4
(P-4) = -4
(
P
−
4
)
=
−
4
Solve first equation:
Solve the first equation
(
P
−
4
)
=
4
(P-4) = 4
(
P
−
4
)
=
4
.
\newline
P
−
4
=
4
P - 4 = 4
P
−
4
=
4
\newline
P
=
4
+
4
P = 4 + 4
P
=
4
+
4
\newline
P
=
8
P = 8
P
=
8
Solve second equation:
Solve the second equation
(
P
−
4
)
=
−
4
(P-4) = -4
(
P
−
4
)
=
−
4
.
P
−
4
=
−
4
P - 4 = -4
P
−
4
=
−
4
P
=
−
4
+
4
P = -4 + 4
P
=
−
4
+
4
P
=
0
P = 0
P
=
0
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