Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

([n+k-1],[n-1])

(n+k1n1) \left(\begin{array}{c}n+k-1 \\ n-1\end{array}\right)

Full solution

Q. (n+k1n1) \left(\begin{array}{c}n+k-1 \\ n-1\end{array}\right)
  1. Identify binomial coefficient notation: Identify the binomial coefficient notation. The binomial coefficient (n+k1,n1)(n+k-1, n-1) is read as n+k1n+k-1 choose n1n-1. This represents the number of ways to choose n1n-1 items from a set of n+k1n+k-1 distinct items without regard to the order of selection.
  2. Use formula: Use the formula for the binomial coefficient. The binomial coefficient can be calculated using the formula:\newline(a,b)=a!b!(ab)!(a,b) = \frac{a!}{b! \cdot (a-b)!}\newlinewhere a!a! denotes the factorial of aa, and aa and bb are non-negative integers with aba \geq b.
  3. Apply formula: Apply the formula to the given binomial coefficient. Substitute aa with n+k1n+k-1 and bb with n1n-1:(n+k1n1)=(n+k1)!(n1)!((n+k1)(n1))!\binom{n+k-1}{n-1} = \frac{(n+k-1)!}{(n-1)! * ((n+k-1)-(n-1))!}
  4. Simplify denominator: Simplify the expression in the denominator. Calculate ((n+k1)(n1))((n+k-1)-(n-1)): ((n+k1)(n1))=n+k1n+1=k((n+k-1)-(n-1)) = n+k-1-n+1 = k
  5. Substitute and simplify: Substitute the simplified expression back into the formula:\newline[n+k1],[n1][n+k-1],[n-1] = (n+k1)!(n1)!k!\frac{(n+k-1)!}{(n-1)! \cdot k!}\newlineThis is the simplified form of the binomial coefficient.

More problems from Multiply powers: integer bases

QuestionGet tutor helpright-arrow

Posted 1 month ago

QuestionGet tutor helpright-arrow

Posted 3 months ago