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(x10)(x+1)\left(x - 10\right)\left(x + 1\right)

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Q. (x10)(x+1)\left(x - 10\right)\left(x + 1\right)
  1. Given expression: We are given the expression (x10)(x+1)(x - 10)(x + 1) and we need to find its product.\newlineTo do this, we will use the distributive property (also known as the FOIL method for binomials) to multiply each term in the first binomial by each term in the second binomial.
  2. Apply distributive property: First, we multiply the first terms of each binomial: x×x=x2x \times x = x^2.
  3. Multiply first terms: Next, we multiply the outer terms: x1=xx * 1 = x.
  4. Multiply outer terms: Then, we multiply the inner terms: 10×x=10x-10 \times x = -10x.
  5. Multiply inner terms: Finally, we multiply the last terms of each binomial: 10×1=10-10 \times 1 = -10.
  6. Multiply last terms: Now, we add all the products together: x2+x10x10x^2 + x - 10x - 10.
  7. Add all products: We combine like terms: x2+x10x=x29xx^2 + x - 10x = x^2 - 9x. So the expression simplifies to x29x10x^2 - 9x - 10.

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