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Let’s check out your problem:

((k+1)(k+2))/(2))^(2)

(k+1)(k+2)2)2 \left.\frac{(k+1)(k+2)}{2}\right)^{2}

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Full solution

Q. (k+1)(k+2)2)2 \left.\frac{(k+1)(k+2)}{2}\right)^{2}
  1. Write Expression to Square: First, let's write down the expression we need to square. ((k+1)(k+2)2)2\left(\frac{(k+1)(k+2)}{2}\right)^2
  2. Square Numerator and Denominator: Now, let's square the numerator and the denominator separately. ((k+1)2⋅(k+2)2)/(22)((k+1)^2 \cdot (k+2)^2) / (2^2)
  3. Simplify Denominator: Simplify the denominator. (k+1)2⋅(k+2)24\frac{(k+1)^2 \cdot (k+2)^2}{4}
  4. Expand Binomials in Numerator: Expand the binomials in the numerator. (k2+2k+1)×(k2+4k+4)/4(k^2 + 2k + 1) \times (k^2 + 4k + 4) / 4
  5. Multiply Binomials: Multiply the binomials together.\newline(k4+6k3+13k2+12k+4)/4(k^4 + 6k^3 + 13k^2 + 12k + 4) / 4

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