Substitution: Let's do a substitution: let u=x2+1, then du=2xdx.
Rewrite in terms of u: Rewrite the integral in terms of u: ∫043(x+1)x2+1dx becomes 21∫11613u(u−1)du.
Split into two parts: Now, let's split the integral into two parts: (\(1/2) \times \left(\int_{1}^{13/16}\frac{du}{u^{3/2}} - \int_{1}^{13/16}\frac{du}{u^{1/2}}\right)\.
Find antiderivatives: Find the antiderivatives: (1/2)⋅(−2/u1/2−2u) from 1 to 13/16.
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