(i) Verify the Mean Value Theorem for y=x3−3x+1 on the interval [−2,2] as follows.(a) Verify that the hypotheses of the Mean value theorem holds.(b) Verify that the conclusion of the Mean value theorem holds.(ii) Illustrate (i-(b)) by a graph involving the extreme chord.
Q. (i) Verify the Mean Value Theorem for y=x3−3x+1 on the interval [−2,2] as follows.(a) Verify that the hypotheses of the Mean value theorem holds.(b) Verify that the conclusion of the Mean value theorem holds.(ii) Illustrate (i-(b)) by a graph involving the extreme chord.
Check Continuity: Check if the function is continuous on the closed interval [−2,2].y=x3−3x+1 is a polynomial, which is continuous everywhere.
Check Differentiability: Check if the function is differentiable on the open interval (−2,2).y=x3−3x+1 is a polynomial, which is differentiable everywhere.
Calculate Average Rate: Calculate the average rate of change of the function on the interval [−2,2].f(2)=23−3(2)+1=8−6+1=3f(−2)=(−2)3−3(−2)+1=−8+6+1=−1Average rate of change = (f(2)−f(−2))/(2−(−2))=(3−(−1))/(4)=4/4=1
Find Derivative: Find the derivative of the function.f′(x)=dxd(x3−3x+1)=3x2−3
Set Derivative Equal: Set the derivative equal to the average rate of change to find the value c in (−2,2).3x2−3=13x2=4x2=34x=±34x=±34x=±32Since we are looking for a value in the interval (−2,2), we take x=32.
Verify Value of c: Verify that this value of c is within the interval (−2,2).32 is approximately 1.15, which is between −2 and 2.
Draw Graph: Draw the graph to illustrate the conclusion of the Mean Value Theorem. The graph should show the function y=x3−3x+1, the secant line connecting the points (−2,f(−2)) and (2,f(2)), and the tangent line at x=32 that is parallel to the secant line.