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Let’s check out your problem:
(e)
x
−
3
x
+
3
=
x
−
2
x
+
2
\frac{x-3}{x+3}=\frac{x-2}{x+2}
x
+
3
x
−
3
=
x
+
2
x
−
2
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Math Problems
Algebra 2
Add and subtract polynomials
Full solution
Q.
(e)
x
−
3
x
+
3
=
x
−
2
x
+
2
\frac{x-3}{x+3}=\frac{x-2}{x+2}
x
+
3
x
−
3
=
x
+
2
x
−
2
Cross-multiply fractions:
Step
1
1
1
: Cross-multiply to eliminate the fractions.
\newline
(
x
−
3
)
(
x
+
2
)
=
(
x
−
2
)
(
x
+
3
)
(x - 3)(x + 2) = (x - 2)(x + 3)
(
x
−
3
)
(
x
+
2
)
=
(
x
−
2
)
(
x
+
3
)
Expand and simplify:
Step
2
2
2
: Expand both sides of the equation.
x
2
+
2
x
−
3
x
−
6
=
x
2
+
3
x
−
2
x
−
6
x^2 + 2x - 3x - 6 = x^2 + 3x - 2x - 6
x
2
+
2
x
−
3
x
−
6
=
x
2
+
3
x
−
2
x
−
6
Combine like terms:
Step
3
3
3
: Simplify by combining like terms.
x
2
−
x
−
6
=
x
2
+
x
−
6
x^2 - x - 6 = x^2 + x - 6
x
2
−
x
−
6
=
x
2
+
x
−
6
Subtract and simplify:
Step
4
4
4
: Subtract
x
2
x^2
x
2
from both sides to simplify further.
\newline
−
x
−
6
=
x
−
6
-x - 6 = x - 6
−
x
−
6
=
x
−
6
Isolate the variable:
Step
5
5
5
: Add
6
6
6
to both sides.
\newline
−
x
=
x
-x = x
−
x
=
x
Add and solve:
Step
6
6
6
: Add
x
x
x
to both sides to isolate the variable.
\newline
0
=
2
x
0 = 2x
0
=
2
x
Final solution:
Step
7
7
7
: Divide both sides by
2
2
2
to solve for
x
x
x
.
x
=
0
x = 0
x
=
0
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(
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−
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\newline
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\text{[[even][odd][neither]]}
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)
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)
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\newline
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x
+
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)
(
x
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x
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\newline
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\newline
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