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(e^(-i))/(-i*(-2i))

e−i−i⋅(−2i) \frac{e^{-i}}{-i \cdot(-2 i)}

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Evaluate integers raised to rational exponentsright chevron icon

Full solution

Q. e−i−i⋅(−2i) \frac{e^{-i}}{-i \cdot(-2 i)}
  1. Identify Components: Identify the components of the expression.\newlineCalculation: We have e(−i)e^{(-i)} in the numerator and −i∗(−2i)-i*(-2i) in the denominator.
  2. Simplify Denominator: Simplify the denominator.\newlineCalculation: −i∗(−2i)=2i2-i*(-2i) = 2i^2.
  3. Remember i2i^2: Remember that i2=−1i^2 = -1.\newlineCalculation: 2i2=2∗(−1)=−22i^2 = 2*(-1) = -2.
  4. Substitute Denominator: Substitute the simplified denominator back into the expression.\newlineCalculation: e−i−2\frac{e^{-i}}{-2}.
  5. Divide Numerator: Divide the numerator by the simplified denominator.\newlineCalculation: (e(−i))/(−2)=−0.5e(−i)(e^{(-i)})/(-2) = -0.5e^{(-i)}.

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