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(d)/(dx)(sin^(2)(x))

ddx(sin2(x)) \frac{d}{d x}\left(\sin ^{2}(x)\right)

Full solution

Q. ddx(sin2(x)) \frac{d}{d x}\left(\sin ^{2}(x)\right)
  1. Recognize Function: Step 11: Recognize the function to differentiate.\newlineWe need to find the derivative of sin2(x)\sin^2(x).
  2. Apply Chain Rule: Step 22: Apply the chain rule for differentiation.\newlineLet u=sin(x)u = \sin(x), then we need to find the derivative of u2u^2.\newlineddx(u2)=2ududx\frac{d}{dx}(u^2) = 2u \cdot \frac{du}{dx}.
  3. Substitute and Simplify: Step 33: Substitute back for uu and dudx\frac{du}{dx}.
    u=sin(x)u = \sin(x) and dudx=cos(x)\frac{du}{dx} = \cos(x).
    So, ddx(sin2(x))=2sin(x)cos(x)\frac{d}{dx}(\sin^2(x)) = 2\sin(x) \cdot \cos(x).
  4. Substitute and Simplify: Step 33: Substitute back for uu and dudx\frac{du}{dx}.u=sin(x)u = \sin(x) and dudx=cos(x)\frac{du}{dx} = \cos(x).So, ddx(sin2(x))=2sin(x)cos(x)\frac{d}{dx}(\sin^2(x)) = 2\sin(x) \cdot \cos(x). Step 44: Simplify the expression.2sin(x)cos(x)2\sin(x)\cos(x) can be written as sin(2x)\sin(2x) using the double angle formula for sine.

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