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(d)/(dx)(log_(10)x+log_(x)10+log_(x)x+log_(10)10)

1111) ddx(log10x+logx10+logxx+log1010) \frac{d}{d x}\left(\log _{10} x+\log _{x} 10+\log _{x} x+\log _{10} 10\right)

Full solution

Q. 1111) ddx(log10x+logx10+logxx+log1010) \frac{d}{d x}\left(\log _{10} x+\log _{x} 10+\log _{x} x+\log _{10} 10\right)
  1. Find Derivative of log10x\log_{10}x: We need to find the derivative of each term separately.\newlineFirst, let's find the derivative of log10x\log_{10}x.\newlineUsing the change of base formula, log10x=ln(x)ln(10)\log_{10}x = \frac{\ln(x)}{\ln(10)}.\newlineThe derivative of ln(x)\ln(x) is 1x\frac{1}{x}, so the derivative of log10x\log_{10}x is 1xln(10)\frac{1}{x\ln(10)}.
  2. Find Derivative of logx10\log_{x}10: Now, let's find the derivative of logx10\log_{x}10. This is an inverse logarithm, so we use the formula ddx(logxa)=1xln(a)\frac{d}{dx}(\log_{x}a) = -\frac{1}{x\ln(a)}. Here, a=10a = 10, so the derivative of logx10\log_{x}10 is 1xln(10)-\frac{1}{x\ln(10)}.
  3. Find Derivative of logxx\log_{x}x: Next, we find the derivative of logxx\log_{x}x. This is a logarithm with the base the same as the argument, which simplifies to 11. The derivative of a constant is 00.
  4. Find Derivative of log1010\log_{10}10: Lastly, we find the derivative of log1010\log_{10}10. This is a constant because it's the log of a number with the same base, so its derivative is also 00.
  5. Sum of Derivatives: Adding up all the derivatives, we get 1xln(10)1xln(10)+0+0\frac{1}{x\ln(10)} - \frac{1}{x\ln(10)} + 0 + 0. This simplifies to 00, since the first two terms cancel each other out.

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