Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Consider the following data on the length of eggs (mm) of two breeds of cuckoo 22.522.5 20.120.1 23.323.3 22.922.9 22.022.0 23.123.1 22.022.0 22.322.3 23.623.6 24.724.7 20.120.100 20.120.111 20.120.122 20.120.133 20.120.144 20.120.155 20.120.166 20.120.1 20.120.188 20.120.188 22.522.5 22.322.3 20.120.188 22.022.0 20.120.155 23.323.3 23.323.366 22.322.3 23.323.388 20.120.100 22.022.0 22.922.911 23.323.366 22.922.933 22.922.944 23.323.3 20.120.111 23.623.6 22.922.988 22.922.9 a. Use a class interval of size 22.022.000, construct a grouped frequency distribution. b. Find first and third Quartile of the distribution c. Obtain the mean and standard deviation d. Show whether second quartile is same as the median of the distribution and comment on your result.

Full solution

Q. Consider the following data on the length of eggs (mm) of two breeds of cuckoo 22.522.5 20.120.1 23.323.3 22.922.9 22.022.0 23.123.1 22.022.0 22.322.3 23.623.6 24.724.7 20.120.100 20.120.111 20.120.122 20.120.133 20.120.144 20.120.155 20.120.166 20.120.1 20.120.188 20.120.188 22.522.5 22.322.3 20.120.188 22.022.0 20.120.155 23.323.3 23.323.366 22.322.3 23.323.388 20.120.100 22.022.0 22.922.911 23.323.366 22.922.933 22.922.944 23.323.3 20.120.111 23.623.6 22.922.988 22.922.9 a. Use a class interval of size 22.022.000, construct a grouped frequency distribution. b. Find first and third Quartile of the distribution c. Obtain the mean and standard deviation d. Show whether second quartile is same as the median of the distribution and comment on your result.
  1. Construct Frequency Distribution: Step 11: Construct a grouped frequency distribution using a class interval of size 55.\newline- Start with the smallest value, which is 20.120.1, and create intervals up to the largest value, which is 24.724.7.\newline- Intervals: [2025)[20-25)\newline- Count the number of eggs in each interval.\newline- Frequency: 4040 (since all values fall within this interval).
  2. Find Quartiles: Step 22: Find the first and third quartiles of the distribution.\newline- Since all values are in one interval, approximate quartiles by dividing the total number of data points.\newline- First Quartile (Q11) = 2525th percentile = 10th10^{th} data point when sorted.\newline- Third Quartile (Q33) = 7575th percentile = 30th30^{th} data point when sorted.\newline- Sorted data: 20.1,20.1,20.4,20.6,20.9,21.0,21.7,21.7,21.9,21.9,21.9,22.0,22.0,22.0,22.0,22.1,22.2,22.2,22.3,22.3,22.3,22.5,22.5,22.7,22.8,22.9,22.9,23.1,23.3,23.3,23.3,23.6,23.6,23.7,23.7,24.0,24.0,24.2,24.4,24.720.1, 20.1, 20.4, 20.6, 20.9, 21.0, 21.7, 21.7, 21.9, 21.9, 21.9, 22.0, 22.0, 22.0, 22.0, 22.1, 22.2, 22.2, 22.3, 22.3, 22.3, 22.5, 22.5, 22.7, 22.8, 22.9, 22.9, 23.1, 23.3, 23.3, 23.3, 23.6, 23.6, 23.7, 23.7, 24.0, 24.0, 24.2, 24.4, 24.7.\newline- Q1=21.9Q1 = 21.9, Q3=23.3Q3 = 23.3.
  3. Calculate Mean and Standard Deviation: Step 33: Calculate the mean and standard deviation.\newline- Mean = (Sum of all values) / Total number of values.\newline- Sum = 891.9891.9, Total values = 4040.\newline- Mean = 891.9/40=22.2975891.9 / 40 = 22.2975.\newline- Standard deviation = (Σ(xmean)2)/n\sqrt{(\Sigma(x - \text{mean})^2) / n}.\newline- Calculations for variance: Σ(x22.2975)2=118.6761\Sigma(x - 22.2975)^2 = 118.6761, Variance = 118.6761/40=2.9669118.6761 / 40 = 2.9669.\newline- Standard deviation = 2.9669=1.7225\sqrt{2.9669} = 1.7225.
  4. Check Median vs. Second Quartile: Step 44: Check if the second quartile is the same as the median.\newline- Second Quartile (Median) = 50th50^{\text{th}} percentile = 20th20^{\text{th}} data point when sorted.\newline- Median = 22.1522.15.\newline- Since the median (22.1522.15) is not exactly the same as the calculated second quartile (22.297522.2975), they are slightly different.

More problems from Volume of cubes and rectangular prisms: word problems