[CA]: (7.3 - 7.57.7)possibleA waitress sold 20 ribeye steak dinners and 12 grilled salmon dinners, totaling $573.12 on a particular day. Another day she sold 26 ribeye steak dinners and 6 grilled salmon dinners, totaling $582.07. How much did each type of dinner cost?□ and the cost of salmon dinners is $□ The cost of ribeye steak dinners is $□ (Simplify your answer. Round to the nearest hundredth as needed.)
Q. [CA]: (7.3 - 7.57.7)possibleA waitress sold 20 ribeye steak dinners and 12 grilled salmon dinners, totaling $573.12 on a particular day. Another day she sold 26 ribeye steak dinners and 6 grilled salmon dinners, totaling $582.07. How much did each type of dinner cost?□ and the cost of salmon dinners is $□ The cost of ribeye steak dinners is $□ (Simplify your answer. Round to the nearest hundredth as needed.)
Define Variables: Let's call the cost of a ribeye steak dinner r and the cost of a grilled salmon dinner s. We have two equations based on the information given: 20r+12s=573.12 (1) 26r+6s=582.07 (2)
Multiply Equation: Multiply equation (2) by 2 to make the coefficient of "s" the same as in equation (1):2(26r+6s)=2(582.07)52r+12s=1164.14(3)
Subtract Equations: Subtract equation (1) from equation (3) to eliminate "s":(52r+12s)−(20r+12s)=1164.14−573.1232r=591.02
Solve for r: Divide both sides by 32 to solve for "r":r=32591.02r=18.47
Substitute and Solve for s: Now substitute the value of r back into equation (1) to solve for s: 20(18.47)+12s=573.12369.4+12s=573.12
Isolate s: Subtract 369.4 from both sides to isolate s:12s=573.12−369.412s=203.72
Final Solution: Divide both sides by 12 to solve for "s":s=12203.72s=16.98
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