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[CA]: (7.3 - 7.5 7.7)
possible
A waitress sold 20 ribeye steak dinners and 12 grilled salmon dinners, totaling 
$573.12 on a particular day. Another day she sold 26 ribeye steak dinners and 6 grilled salmon dinners, totaling 
$582.07. How much did each type of dinner cost?

◻ and the cost of salmon dinners is 
$ 
◻ The cost of ribeye steak dinners is 
$ 
◻ (Simplify your answer. Round to the nearest hundredth as needed.)

[CA]: (77.33 - 77.55 77.77)\newlinepossible\newlineA waitress sold 2020 ribeye steak dinners and 1212 grilled salmon dinners, totaling $573.12 \$ 573.12 on a particular day. Another day she sold 2626 ribeye steak dinners and 66 grilled salmon dinners, totaling $582.07 \$ 582.07 . How much did each type of dinner cost?\newline \square and the cost of salmon dinners is $ \$ \square The cost of ribeye steak dinners is $ \$ \square (Simplify your answer. Round to the nearest hundredth as needed.)

Full solution

Q. [CA]: (77.33 - 77.55 77.77)\newlinepossible\newlineA waitress sold 2020 ribeye steak dinners and 1212 grilled salmon dinners, totaling $573.12 \$ 573.12 on a particular day. Another day she sold 2626 ribeye steak dinners and 66 grilled salmon dinners, totaling $582.07 \$ 582.07 . How much did each type of dinner cost?\newline \square and the cost of salmon dinners is $ \$ \square The cost of ribeye steak dinners is $ \$ \square (Simplify your answer. Round to the nearest hundredth as needed.)
  1. Define Variables: Let's call the cost of a ribeye steak dinner rr and the cost of a grilled salmon dinner ss. We have two equations based on the information given: 20r+12s=573.1220r + 12s = 573.12 (11) 26r+6s=582.0726r + 6s = 582.07 (22)
  2. Multiply Equation: Multiply equation (22) by 22 to make the coefficient of "s" the same as in equation (11):\newline2(26r+6s)=2(582.07)2(26r + 6s) = 2(582.07)\newline52r+12s=1164.14(3)52r + 12s = 1164.14 \quad (3)
  3. Subtract Equations: Subtract equation (11) from equation (33) to eliminate "s":\newline(52r+12s)(20r+12s)=1164.14573.12(52r + 12s) - (20r + 12s) = 1164.14 - 573.12\newline32r=591.0232r = 591.02
  4. Solve for r: Divide both sides by 3232 to solve for "r":\newliner=591.0232r = \frac{591.02}{32}\newliner=18.47r = 18.47
  5. Substitute and Solve for s: Now substitute the value of rr back into equation (11) to solve for ss: \newline20(18.47)+12s=573.1220(18.47) + 12s = 573.12\newline369.4+12s=573.12369.4 + 12s = 573.12
  6. Isolate ss: Subtract 369.4369.4 from both sides to isolate ss:12s=573.12369.412s = 573.12 - 369.412s=203.7212s = 203.72
  7. Final Solution: Divide both sides by 1212 to solve for "s":\newlines=203.7212s = \frac{203.72}{12}\newlines=16.98s = 16.98

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