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(ax+5)(x+v)=ax^(2)+25 x+25
What is the value of 
a in the given equation?
Choose 1 answer:
(A) -5
(B) -4
(C) 4
(D) 5

(ax+5)(x+v)=ax2+25x+25 (a x+5)(x+v)=a x^{2}+25 x+25 \newlineWhat is the value of a a in the given equation?\newlineChoose 11 answer:\newline(A) 5-5\newline(B) 4-4\newline(C) 44\newline(D) 55

Full solution

Q. (ax+5)(x+v)=ax2+25x+25 (a x+5)(x+v)=a x^{2}+25 x+25 \newlineWhat is the value of a a in the given equation?\newlineChoose 11 answer:\newline(A) 5-5\newline(B) 4-4\newline(C) 44\newline(D) 55
  1. Expand Left Side: Expand the left side of the equation (ax+5)(x+v)(ax+5)(x+v) using the distributive property (FOIL method).(ax+5)(x+v)=axx+axv+5x+5v(ax+5)(x+v) = ax\cdot x + ax\cdot v + 5\cdot x + 5\cdot v
  2. Compare with Right Side: Compare the expanded form with the right side of the equation ax2+25x+25ax^2 + 25x + 25. We have ax×x=ax2ax \times x = ax^2, which is already in the correct form. Now, we need to find the terms that combine to give us 25x25x on the right side.
  3. Find Terms for 25x25x: The terms axvax*v and 5x5*x must add up to 25x25x.\newlineSo, axv+5x=25xax*v + 5*x = 25x.
  4. Deduce Value of vv: Since there is no xx term on the left side that would correspond to 25x25x on the right side, we can deduce that vv must be 55 to satisfy the equation.\newlineThis is because 5×x5\times x is already part of the 25x25x term on the right side, so ax×vax\times v must be the remaining 20x20x.
  5. Simplify Equation: Now we have ax×5+5×x=20x+5x=25xax \times 5 + 5 \times x = 20x + 5x = 25x. This simplifies to 5a×x+5×x=25x5a \times x + 5 \times x = 25x.
  6. Divide and Solve for aa: Divide the entire equation by xx to simplify and solve for aa.5a+5=255a + 5 = 25.
  7. Subtract to Isolate aa: Subtract 55 from both sides to isolate the term with aa.5a=255.5a = 25 - 5.
  8. Calculate Value of a: Calculate the value of a.\newline5a=205a = 20.\newlinea=205a = \frac{20}{5}.\newlinea=4a = 4.
  9. Final Answer: The value of aa is 44, which corresponds to option (C)(C).

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