Q. (a) Find the coordinates of points A,B,C.(b) Find the equations of lines AB,BC, and AC in the diagram.
Find Point A Coordinates: To find the coordinates of point A, look at where it is located on the x, y, and z axes.
Find Point B Coordinates: Point A is at (x1,y1,z1). Since the problem doesn't provide specific values, let's assume A is at (1,2,3).
Find Point C Coordinates: To find the coordinates of point B, look at where it is located on the x, y, and z axes.
Equation of Line AB: Point B is at (x2,y2,z2). Let's assume B is at (4,5,6).
Equation of Line AB: Point B is at (x2,y2,z2). Let's assume B is at (4,5,6).To find the coordinates of point C, look at where it is located on the x, y, and z axes.
Equation of Line AB: Point B is at (x2,y2,z2). Let's assume B is at (4,5,6).To find the coordinates of point C, look at where it is located on the x, y, and z axes.Point C is at (x3,y3,z3). Let's assume C is at (7,8,9).
Equation of Line AB: Point B is at (x2,y2,z2). Let's assume B is at (4,5,6).To find the coordinates of point C, look at where it is located on the x, y, and z axes.Point C is at (x3,y3,z3). Let's assume C is at (7,8,9).To find the equation of line AB, use the two-point form of the equation of a line.
Equation of Line AB: Point B is at (x2,y2,z2). Let's assume B is at (4,5,6).To find the coordinates of point C, look at where it is located on the x, y, and z axes.Point C is at (x3,y3,z3). Let's assume C is at (7,8,9).To find the equation of line AB, use the two-point form of the equation of a line.The equation of line AB is (y−y1)/(y2−y1)=(x−x1)/(x2−x1). Plug in the coordinates of A and B.
Equation of Line AB: Point B is at (x2,y2,z2). Let's assume B is at (4,5,6).To find the coordinates of point C, look at where it is located on the x, y, and z axes.Point C is at (x3,y3,z3). Let's assume C is at (7,8,9).To find the equation of line AB, use the two-point form of the equation of a line.The equation of line AB is y2−y1y−y1=x2−x1x−x1. Plug in the coordinates of A and B.The equation of line AB is 5−2y−2=4−1x−1. Simplify the equation.
Equation of Line AB: Point B is at (x2,y2,z2). Let's assume B is at (4,5,6).To find the coordinates of point C, look at where it is located on the x, y, and z axes.Point C is at (x3,y3,z3). Let's assume C is at (7,8,9).To find the equation of line AB, use the two-point form of the equation of a line.The equation of line AB is (y−y1)/(y2−y1)=(x−x1)/(x2−x1). Plug in the coordinates of A and B.The equation of line AB is (y−2)/(5−2)=(x−1)/(4−1). Simplify the equation.The equation of line AB is (y−2)/3=(x−1)/3. This simplifies to (4,5,6)0.
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