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/_A=6x-35^(@)quad/_B=3x+53^(@) Solve for x and then find the measure of /_A :

∠A=6x−35∘∠B=3x+53∘ \angle A=6 x-35^{\circ} \quad \angle B=3 x+53^{\circ} \newlineSolve for x x and then find the measure of ∠A \angle A :

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Q. ∠A=6x−35∘∠B=3x+53∘ \angle A=6 x-35^{\circ} \quad \angle B=3 x+53^{\circ} \newlineSolve for x x and then find the measure of ∠A \angle A :
  1. Set up equation: Since ∠A\angle A and ∠B\angle B are angles, if they are supplementary (which is often the case when two angles are presented together), their measures add up to 180180 degrees. So, we set up the equation:\newline6x−35+3x+53=1806x - 35 + 3x + 53 = 180
  2. Combine like terms: Combine like terms: 9x+18=1809x + 18 = 180

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