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(a^(2)-b^(2)+2a+1)/(a+1+b)= ?
A) 
a+3b+1
B) 
3a-b+1
C) 
a-b+1
D) 
a-b+3
E) 
a+b-1

4040. a2b2+2a+1a+1+b= \frac{a^{2}-b^{2}+2 a+1}{a+1+b}= ?\newlineA) a+3b+1 a+3 b+1 \newlineB) 3ab+1 3 a-b+1 \newlineC) ab+1 a-b+1 \newlineD) ab+3 a-b+3 \newlineE) a+b1 a+b-1

Full solution

Q. 4040. a2b2+2a+1a+1+b= \frac{a^{2}-b^{2}+2 a+1}{a+1+b}= ?\newlineA) a+3b+1 a+3 b+1 \newlineB) 3ab+1 3 a-b+1 \newlineC) ab+1 a-b+1 \newlineD) ab+3 a-b+3 \newlineE) a+b1 a+b-1
  1. Recognize Quadratic Expression: First, recognize that the numerator is a quadratic expression that can be factored. The term a2b2a^2 - b^2 is a difference of squares, which factors into (ab)(a+b)(a - b)(a + b). The remaining terms 2a+12a + 1 do not factor with the difference of squares, so we will keep them separate for now.
  2. Factor Numerator: Now, let's factor the numerator: a2b2+2a+1=(ab)(a+b)+2a+1a^2 - b^2 + 2a + 1 = (a - b)(a + b) + 2a + 1.
  3. Look for Common Factors: Next, we need to look for common factors between the numerator and the denominator. The denominator is a+1+ba + 1 + b, which can be reordered as (a+b+1)(a + b + 1) to make it easier to compare with the numerator.
  4. Expand and Simplify Numerator: We can see that there is no common factor between (ab)(a+b)+2a+1(a - b)(a + b) + 2a + 1 and a+b+1a + b + 1, so we cannot simplify the expression by canceling out any terms. Therefore, we need to expand the numerator and then simplify the expression.
  5. Factor Perfect Square Trinomial: Let's expand the numerator: (ab)(a+b)+2a+1=a2b2+2a+1(a - b)(a + b) + 2a + 1 = a^2 - b^2 + 2a + 1.
  6. Rewrite with Factored Numerator: Now, we will simplify the numerator by combining like terms: a2b2+2a+1=a2+2a+1b2a^2 - b^2 + 2a + 1 = a^2 + 2a + 1 - b^2.
  7. Simplify by Canceling Common Factor: Notice that a2+2a+1a^2 + 2a + 1 is a perfect square trinomial, which factors into (a+1)2(a + 1)^2. So the numerator becomes (a+1)2b2(a + 1)^2 - b^2.
  8. Final Simplified Expression: We can now rewrite the expression with the factored numerator: ((a+1)2b2)/(a+b+1)((a + 1)^2 - b^2) / (a + b + 1).
  9. Final Simplified Expression: We can now rewrite the expression with the factored numerator: (a+1)2b2a+b+1\frac{(a + 1)^2 - b^2}{a + b + 1}.The numerator is now a difference of squares again, with (a+1)2(a + 1)^2 being the square of (a+1)(a + 1) and b2b^2 being the square of bb. We can factor the numerator as ((a+1)b)((a+1)+b)((a + 1) - b)((a + 1) + b).
  10. Final Simplified Expression: We can now rewrite the expression with the factored numerator: (a+1)2b2a+b+1\frac{(a + 1)^2 - b^2}{a + b + 1}.The numerator is now a difference of squares again, with (a+1)2(a + 1)^2 being the square of (a+1)(a + 1) and b2b^2 being the square of bb. We can factor the numerator as ((a+1)b)((a+1)+b)((a + 1) - b)((a + 1) + b).After factoring, the expression becomes: (a+1b)(a+1+b)a+b+1\frac{(a + 1 - b)(a + 1 + b)}{a + b + 1}.
  11. Final Simplified Expression: We can now rewrite the expression with the factored numerator: ((a+1)2b2)/(a+b+1)((a + 1)^2 - b^2) / (a + b + 1).The numerator is now a difference of squares again, with (a+1)2(a + 1)^2 being the square of (a+1)(a + 1) and b2b^2 being the square of bb. We can factor the numerator as ((a+1)b)((a+1)+b)((a + 1) - b)((a + 1) + b).After factoring, the expression becomes: ((a+1b)(a+1+b))/(a+b+1)((a + 1 - b)(a + 1 + b)) / (a + b + 1).Now, we can simplify the expression by canceling out the common factor of (a+b+1)(a + b + 1) in the numerator and denominator. However, we must be careful here because the numerator has (a+1b)(a + 1 - b) and (a+1+b)(a + 1 + b), which are not the same as (a+b+1)(a + b + 1). There is no common factor to cancel out, so the expression cannot be simplified further.
  12. Final Simplified Expression: We can now rewrite the expression with the factored numerator: ((a+1)2b2)/(a+b+1)((a + 1)^2 - b^2) / (a + b + 1). The numerator is now a difference of squares again, with (a+1)2(a + 1)^2 being the square of (a+1)(a + 1) and b2b^2 being the square of bb. We can factor the numerator as ((a+1)b)((a+1)+b)((a + 1) - b)((a + 1) + b). After factoring, the expression becomes: ((a+1b)(a+1+b))/(a+b+1)((a + 1 - b)(a + 1 + b)) / (a + b + 1). Now, we can simplify the expression by canceling out the common factor of (a+b+1)(a + b + 1) in the numerator and denominator. However, we must be careful here because the numerator has (a+1b)(a + 1 - b) and (a+1+b)(a + 1 + b), which are not the same as (a+b+1)(a + b + 1). There is no common factor to cancel out, so the expression cannot be simplified further. The final simplified expression is ((a+1b)(a+1+b))/(a+b+1)((a + 1 - b)(a + 1 + b)) / (a + b + 1), which does not match any of the answer choices provided. It seems there might have been a mistake in the simplification process. Let's re-evaluate the expression.

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