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{:[-9y+18=-3x],[4x-3y-3=0]:}

33)\newline9y+18=3x4x3y3=0 \begin{array}{l} -9 y+18=-3 x \\ 4 x-3 y-3=0 \end{array}

Full solution

Q. 33)\newline9y+18=3x4x3y3=0 \begin{array}{l} -9 y+18=-3 x \\ 4 x-3 y-3=0 \end{array}
  1. Rearrange to solve for y: First, let's rearrange the first equation to get y by itself.\newline9y+18=3x-9y + 18 = -3x\newlineAdd 9y9y to both sides:\newline18=3x+9y18 = -3x + 9y\newlineNow divide everything by 99 to solve for y:\newliney=(3x+18)/9y = (-3x + 18) / 9\newliney=13x+2y = -\frac{1}{3}x + 2
  2. Use second equation for x: Now let's use the second equation to solve for x.\newline4x3y3=04x - 3y - 3 = 0\newlineAdd 33 to both sides:\newline4x3y=34x - 3y = 3\newlineNow let's substitute the yy we found from the first equation into this one.\newline4x3(13x+2)=34x - 3(-\frac{1}{3}x + 2) = 3
  3. Substitute yy into second equation: Distribute the 3-3 to both terms inside the parentheses.4x+x6=34x + x - 6 = 3Now combine like terms.5x6=35x - 6 = 3
  4. Solve for x: Add 66 to both sides to solve for xx. \newline5x=95x = 9\newlineNow divide by 55:\newlinex=95x = \frac{9}{5}\newlinex=1.8x = 1.8
  5. Plug xx back into yy equation: Now that we have xx, let's plug it back into the equation we found for yy.\newliney=13(1.8)+2y = -\frac{1}{3}(1.8) + 2\newliney=0.6+2y = -0.6 + 2\newliney=1.4y = 1.4

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