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$\left(-\left(\frac{9}{2}\right)\right)/\left(\left(\frac{9}{7}\right)\right)$

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Multiplication with rational exponents

Full solution

Q.

\left(-\left(\frac{9}{2}\right)\right)/\left(\left(\frac{9}{7}\right)\right)

Identify Operation: Step $1$ : Identify the operation needed to simplify the expression. $\newline$ We need to divide $-(9)/(2)$ by $(9)/(7)$ . $\newline$ Calculation: $-(9)/(2) ÷ (9)/(7)$
Convert to Multiplication: Step $2$ : Convert the division of fractions into multiplication by the reciprocal. $\newline$ To divide by a fraction, multiply by its reciprocal. $\newline$ Calculation: $-(9)/(2) * (7)/(9)$
Multiply Numerators and Denominators: Step $3$ : Multiply the numerators and the denominators. $\newline$ Multiply $-9$ by $7$ and $2$ by $9$ . $\newline$ Calculation: $(-9 * 7) / (2 * 9) = -63 / 18$
Simplify Fraction: Step $4$ : Simplify the fraction. $\newline$ Divide both the numerator and the denominator by their greatest common divisor, which is $9$ . $\newline$ Calculation: $(-63 ÷ 9) / (18 ÷ 9) = -7 / 2$

More problems from Multiplication with rational exponents

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h(x)=\log _{2}(x)

\newline

Can we use the mean value theorem to say the equation

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1<x<2

\newline

1

\newline

(A) No, since the function is not differentiable on that interval.

\newline

(B) No, since the average rate of change of

h

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1 \leq x \leq 2

1

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(C) Yes, both conditions for using the mean value theorem have been met.

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(C) Neither positive nor negative-the sum is zero.

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Question

\begin{array}{l} g(x)=\sqrt{2 x-9} \\ g^{\prime}(x)=? \end{array}

\newline

1

\newline

\frac{\sqrt{2 x-9}}{2}

\newline

\frac{1}{\sqrt{2 x-9}}

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\frac{1}{2 \sqrt{2 x-9}}

\newline

\frac{1}{\sqrt{x}}

Posted 3 months ago