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(8-i)-(-82+2i)=
Express your answer in the form
(a+bi).

$(8-i)-(-82+2 i)=$ $\newline$ Express your answer in the form $(a+b i)$ .

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Add, subtract, multiply, and divide complex numbers

Full solution

Q.

(8-i)-(-82+2 i)=

\newline

Express your answer in the form

(a+b i)

.

Distribute negative sign: First, we need to distribute the negative sign to both terms in the second complex number, $-(-82+2i)$ . This means we will change the sign of both terms inside the parentheses.
Subtract real parts: Now, we subtract the real parts and the imaginary parts separately. The real part of the first complex number is $8$ , and the real part of the second complex number is $-82$ (after distributing the negative sign). The imaginary part of the first complex number is $-i$ , and the imaginary part of the second complex number is $-2i$ (after distributing the negative sign).
Subtract imaginary parts: Perform the subtraction for the real parts: $8 - (-82) = 8 + 82 = 90$ .
Combine results: Perform the subtraction for the imaginary parts: $-i - (-2i) = -i + 2i = i$ .
Combine results: Perform the subtraction for the imaginary parts: $-i - (-2i) = -i + 2i = i$ . Combine the results of the real part and the imaginary part to express the answer in the form $a+bi$ : $90 + i$ .

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